On the topic of quadrilateral properties and formulas, we have briefly discussed the various shape, properties, and shortcut formulas. Square is one of the important figures of the quadrilateral. Today we are going to solve some mensuration problems related to the square. As you have learned, the square is a four equal-armed and right angular figure. Before solving square mensuration, please read the opening tutorial on quadrilateral properties and mensuration tricks if you need them.
Solution: The arm length of the square is 20m. So the area will be (Arm * Arm) square unit. So area= 20*20 Sq metre =400 sq metre.
The perimeter is the outer length of the figure. The perimeter of the square is (4*Arm). So, perimeter = 4*20 = 80 metre.
Mensuration problem 2: The diagonal of a square is 10√2. Now find the area of the square.
Solution: Look below how we find the area of the square.
Square mensuration
Problem 1: Find the area and perimeter of a 20 meters armed square.Solution: The arm length of the square is 20m. So the area will be (Arm * Arm) square unit. So area= 20*20 Sq metre =400 sq metre.
The perimeter is the outer length of the figure. The perimeter of the square is (4*Arm). So, perimeter = 4*20 = 80 metre.
Mensuration problem 2: The diagonal of a square is 10√2. Now find the area of the square.
Solution: Look below how we find the area of the square.
Read more Triangle properties and Shortcut formula
Circle properties and shortcut formula
Problem 3: 20 meters and 40 meters armed two square land marge into a rectangular land, if the base of the rectangular lad is 50 meters then find the width of the land.
Solution: To solve the mensuration problem, we have to calculate the sum of the area of both squares, which is the area of rectangular land. Look at the below how we solved it.
Problem 4: A house owner wants to cover a courtyard with marvels. The courtyard's base and width are 10 and 8 meters, respectively. The area of each marvel is 1/4 sq meter. Then how many marvels should we have to buy to cover the courtyard?
Solution: We can solve this mensuration problem easily without pen and paper. First of all, we will calculate the area of the courtyard. As the courtyard is rectangular, the area can be calculated by multiplying by base and width. Area= 10*8 sq metre
=80 sq meter. Now we have to divide the courtyard area by the area of a marvel tile. 80/(1/4)=80*4
=320 tile needs to cover the courtyard.
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